Row and column given the position?

[Asmodian]

Chemical.Row = int((i-i%cols)/cols+1) if i%cols > 0 else int((i-i%cols)/cols)

Is there a better way to get the row and column given the position? I have been using this method for years, but it has always felt like there should be a simpler way to do it.

[LoRd_MuldeR]

Assuming row-major order as well as zero-based indexing:

row_index = address / num_columns;  /* integer division (truncating) */
col_index = address % num_columns;  /* modulo operation */

[StainlessS]

Originally Posted by LoRd_MuldeR

Assuming row-major order as well as zero-based indexing:

row_index = address / num_columns;  /* integer division (truncating) */
col_index = address % num_columns;  /* modulo operation */

I think he's wanting Python solution,

So assuming address and num_columns both +ve integer, AND zero-based indexing, maybe just

row_index = address // num_columns 
col_index = address %  num_columns

AFTER HERE is just me Waffling

Easier {for me} to do in C or even Avisynth script than in Python [I dont speak Python].

On looking at OP, I was not sure if was written to also cope with -ve address AND array subscript results [end relative or something, seemed overly complicated].

From here[Learn X in Y minutes<Python>]:- https://learnxinyminutes.com/docs/python/

# Math is what you would expect
1 + 1 # => 2
8 - 1 # => 7
10 * 2 # => 20
35 / 5 # => 7.0

# Integer division rounds down for both positive and negative numbers.
5 // 3 # => 1
-5 // 3 # => -2
5.0 // 3.0 # => 1.0 # works on floats too
-5.0 // 3.0 # => -2.0
# The result of division is always a float
10.0 / 3 # => 3.3333333333333335 # EDIT: I think that means also 10 / 3 => 3.3333333333333335

# Modulo operation
7 % 3 # => 1
# i % j have the same sign as j, unlike C
-7 % 3 # => 2

EDIT:

# Avisynth Script
blankclip
Subtitle(String(  -7 / 3  ),size=48)        # result = -2    
Subtitle(String(  -7 % 3  ),Y=100,size=48)  # result = -1 : ie  (-2*3) + -1 => -7
return last

# I think Python -7 // 3 => -3
# I think Python -7  % 3 =>  2 : ie, (-3*3) + 2 => -7

EDIT:

On looking at OP, I was not sure if was written to also cope with -ve address AND array subscript results [end relative or something, seemed overly complicated].

From Python X in Y minutes thingy

# li is now [1, 2, 4, 3] again.
# Access a list like you would any array
li[0] # => 1
# Look at the last element
li[-1] # => 3