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Old 25th October 2013, 11:36   #1  |  Link
Chainmax
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Can FreezeFrame be applied iteratively?

Let's say I have a video where bad frames fall more or less within a formula like x+y*n, for example, 175+20n (so, 175, 195, 215, etc...). Is there a way to have all the frames in falling in that formula be replaced by their following one with FreezeFrame? If not, what would you suggest to replicate it with?
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Old 25th October 2013, 12:27   #2  |  Link
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I think it could be done using stickboy's ApplyEvery plugin in some way, but I don't have time to work out the details right now.
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Old 25th October 2013, 19:10   #3  |  Link
martin53
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In Runtime Environment (untested),
Code:
c
ScriptClip("""
    c = last
    current_frame % n == x ? c.DeleteFrame(0) : c
""")
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Old 25th October 2013, 19:18   #4  |  Link
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And I think also (assume to replace 2nd frame in group of 4)
Code:
Interleave(c, c.DeleteFrame(0), c.DeleteFrame(0,1,2), c.DeleteFrame(0,1,2)).SelectEvery(4)
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Old 25th October 2013, 19:40   #5  |  Link
Gavino
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Quote:
Originally Posted by martin53 View Post
Code:
Interleave(c, c.DeleteFrame(0), c.DeleteFrame(0,1,2), c.DeleteFrame(0,1,2)).SelectEvery(4)
Doesn't that just give c?
(Interleaving 4 clips and taking the first frame of each group of 4 will give you the frames of the first clip.)
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Old 25th October 2013, 20:54   #6  |  Link
martin53
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Quote:
Originally Posted by Gavino View Post
Doesn't that just give c?
Code:
Interleave(c, c.DeleteFrame(0), c.DeleteFrame(0,1,2), c.DeleteFrame(0,1,2)).SelectEvery(4)
Without the blue '2', yes. But I expect with the blue '2', the third frame (I accidentally wrote 2nd when I meant #2 counted from #0) is in fact one frame ahead.

EDIT: No, you are right, Gavino. SelectEvery takes only the 1st of the interleave group, which is c. Instead it should read
Code:
Interleave(c.SelectEvery(4), c.SelectEvery(4,1), c.SelectEvery(4,3), c.SelectEvery(4,3))

Last edited by martin53; 25th October 2013 at 21:02.
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Old 25th October 2013, 21:37   #7  |  Link
Gavino
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Quote:
Originally Posted by martin53 View Post
Code:
Interleave(c.SelectEvery(4), c.SelectEvery(4,1), c.SelectEvery(4,3), c.SelectEvery(4,3))
That can be written simply as
c.SelectEvery(4, 0,1,3,3)
which works for the example you gave.

The original problem had groups of 20, which is more tedious to do this way (but clearly possible), but imagine if you wanted to freeze, say, every 100th frame, it starts to become a pain.
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Old 25th October 2013, 22:27   #8  |  Link
Gavino
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Quote:
Originally Posted by Gavino View Post
I think it could be done using stickboy's ApplyEvery plugin in some way, but I don't have time to work out the details right now.
This should work for the problem originally described (replace frames 175+20*n by following ones):
Code:
start = Trim(0, 174)
Trim(175, 0)
start + InterleaveEvery(DeleteEvery(20), SelectEvery(20,1), 20)
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Last edited by Gavino; 25th October 2013 at 22:30.
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Old 14th November 2013, 04:19   #9  |  Link
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Thanks for the suggestion, I'll try it and get back you.
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