View Full Version : Help IVTC this silent film
rcjc
9th September 2005, 22:06
using telecide(order=1,post=0) I found the frame pattern to be
0010001000100100010001001000100010001 (repeats)
where 1 is a duplicate.
I'm trying different decimate cycles but nothing seems to get them all. I can't find the right combination of cycles. Can anyone help?
Leak
9th September 2005, 22:18
using telecide(order=1,post=0) I found the frame pattern to be
0010001000100100010001001000100010001 (repeats)
where 1 is a duplicate.
I'm trying different decimate cycles but nothing seems to get them all. I can't find the right combination of cycles. Can anyone help?
Well, if the pattern stays constant throughout the movie, your best bet would probably be using SelectEvery() to get all non-repeated frames out of your cycle.
If it's not constant, it's probably a job for FDecimate or TIVTC...
Don't quote me on that, though... :)
np: Galoppierende Zuversicht LIVE @ [KONTROL] San Francisco - 18.06.2005
rcjc
10th September 2005, 01:21
yea it's constant, I'll try that thx
originally I was trying to see if I could do something like this
http://forum.doom9.org/showthread.php?s=&threadid=30709
scharfis_brain
10th September 2005, 01:35
if the pattern you posted is constant, your true framerate is:
[container framerate] * (1 - [duplicated frames per cycle] / [total number of frames per cycle]) = true framerate
29.97 fps * (1 - 10 / 37) = 21.87 fps
use fdecimete or tdecimate.
or provide an unprocessed sample clip.
manono
10th September 2005, 11:19
Hi-
That's a common pattern used to approximate 22fps (as scharfi says, it's 21.87fps). I would use:
B=TDeint(Mode=1) #or (Leak)KernelBob
SmartDecimate(27,74,B) #very fast
or:
TFM()
TDecimate(Mode=0,CycleR=10,Cycle=37) #somewhat slower
As near as I can tell, you can't get it exactly with Decomb.
rcjc
11th September 2005, 02:14
thanks for the help! :thanks:
vBulletin® v3.8.11, Copyright ©2000-2026, vBulletin Solutions Inc.