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View Full Version : How much is the code intensity of Helix DRM 10 ?


lunaticmoon
24th September 2004, 02:44
I explored a little Web.
However, about the encoding technology or the structure which are used for DRM technology, it does not understand that it is detailed.

Does DRM become spoilt if these information is exhibited ?

Is it better or worse than a RSA 128bit public key code system, or isn't there any prospect of a grade?

Although it is interested also about Microsoft DRM, when it compares, how is it?

They have been only questions.:confused:


EDIT

If it thinks well, this may be the subject about a container.

@moderator

If you judge that it is not suitable here, please move this thread to the container forum.
(In that case, it may be able to argue also about Microsoft DRM.)

Sirber
24th September 2004, 12:33
RSA @ 128bit is not secure. RSA is a public/private key encryption system and need at least 1024 bits to be secure.

lunaticmoon
8th October 2004, 01:09
Although thought over, it is because the standard of being "Secure" is relative, and it is good if an object is what period secret.

In the point that RSA 576bit was already broken, 1024 bits is a realistic value.

RSA 1024bit receives which. Can it be called "Secure"?
Protection of copyrights, finance, military affairs, or the government?

Sirber
8th October 2004, 02:18
RSA@1024 is secure. My PGP key (RSA) is 4096bits for fun :D

You can read more on that topic here:
http://senderek.de/security/secret-key.protection.html

karl_lillevold
9th October 2004, 04:57
It is impossible to make a completely secure DRM.. but it can be made so hard to break, no one will manage within their lifetime. In addition, enforced updates, /in case/ it is broken, needs to be built in. I am sure most used DRMs are that way today, well maybe except one well known exception ..

Sirber
9th October 2004, 05:05
Was it related to a rainbow fruit? :rolleyes: