Mr.Bitey
20th April 2004, 12:03
Hi All,
Im trying to work out what the biggest ISO image is that I can burn to DVD-R media.
I tired to use record now max 4.5 to burn an ISO 4,706,871,296 bytes big (according to dvddecrypter) and it failed with a 'sense key error' (which i get when I burn something too big with record now max - it doesnt tell me its too big which really annoys me, but thats another story! :) )
Interestingly, I burnt an iso image 4,706,916,352 bytes big using dvddecrypter and it burnt ok and verified OK.
DVD Decrypter tells me the blank dvd media holds 2,298,496 sectors, which equals 4,707,319,808 bytes
Using my example, this leaves 403,456 bytes 'free' on the dvd-r, however I was under the impression that the file system takes 858 sectors (or 1,757,184 bytes)... which there clearly isnt enough room for :)
So am I to understand that the ISO image includes the filesystem, thus I should be able to burn an ISO image equaling the maximum capacity of the media? Hence record now max is doing something unusual?
Help :-)
Regards,
Mr.Bitey
Im trying to work out what the biggest ISO image is that I can burn to DVD-R media.
I tired to use record now max 4.5 to burn an ISO 4,706,871,296 bytes big (according to dvddecrypter) and it failed with a 'sense key error' (which i get when I burn something too big with record now max - it doesnt tell me its too big which really annoys me, but thats another story! :) )
Interestingly, I burnt an iso image 4,706,916,352 bytes big using dvddecrypter and it burnt ok and verified OK.
DVD Decrypter tells me the blank dvd media holds 2,298,496 sectors, which equals 4,707,319,808 bytes
Using my example, this leaves 403,456 bytes 'free' on the dvd-r, however I was under the impression that the file system takes 858 sectors (or 1,757,184 bytes)... which there clearly isnt enough room for :)
So am I to understand that the ISO image includes the filesystem, thus I should be able to burn an ISO image equaling the maximum capacity of the media? Hence record now max is doing something unusual?
Help :-)
Regards,
Mr.Bitey