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View Full Version : @Math people:

sh0dan
11th July 2003, 14:07
I need someone to gove me a hand here:

x = pow(10.0, y/20.0);

y = ?
Wilbert
11th July 2003, 14:21
x = 10^(y/20) => y/20 = log_10(x) => y = 20*log_10(x) = 10*log_10(x^2)

some kind of powerspectrum ...
sh0dan
11th July 2003, 14:32
One of my friends suggested:

y = 8,68489 * log(x)

Seems to give correct result.
Wilbert
11th July 2003, 14:41
y = 20*log_10(x) = 20*log_e(10)*log_e(x) = 8.685889638*log_e(x)

both are correct (only the base is different 10 resp. e) ...
sh0dan
11th July 2003, 14:57
Great! Thanks a bunch!