4th alphabet
25th June 2002, 07:56
hi, i recently tried fitting an 89min movie onto a single disc MPEG1 VCD. the bitrate calculation on DVD2SVCD for 89mins on an 80min CD-R is 1023kbit/sec. so i set the max, min, min avg, and max avg all to 1000kbit/sec. am i understanding this correctly? cos the result i got were 2 files, one 79min long and the other was 10min.
does the estimated bitrate calculation include the audio bitrate as well? like in the example above, 1023kbit/sec would mean the total of the video AND audio bitrates. so if my audio bitrate was 192kbit, would i have to set the max, min, min avg, and max avg to 1023-192 = 831kbit?
i always assumed the bitrate did not include audio because for a standard VCD of 1150kbit/sec video and 224kbit/sec audio the total bitrate would be 1374kbit/sec. but according to the bitrate calculation 80mins on an 80min CD-R would use 1161kbit/sec. if this figure was for video alone that would be correct, but if it includes audio as well, it means a standard VCD wouldn't be able to fit 80mins on an 80min CD-R, which it does.
hope i'm making some sense here. i just need help in understanding the bitrate calculation. any guides i could look at?
thanks!
does the estimated bitrate calculation include the audio bitrate as well? like in the example above, 1023kbit/sec would mean the total of the video AND audio bitrates. so if my audio bitrate was 192kbit, would i have to set the max, min, min avg, and max avg to 1023-192 = 831kbit?
i always assumed the bitrate did not include audio because for a standard VCD of 1150kbit/sec video and 224kbit/sec audio the total bitrate would be 1374kbit/sec. but according to the bitrate calculation 80mins on an 80min CD-R would use 1161kbit/sec. if this figure was for video alone that would be correct, but if it includes audio as well, it means a standard VCD wouldn't be able to fit 80mins on an 80min CD-R, which it does.
hope i'm making some sense here. i just need help in understanding the bitrate calculation. any guides i could look at?
thanks!