Divide by rational number

[Terka]

f=1.73
b=a.LanczosResize(width(a)/f,height(a)/f)

does not work.
what is wrong?

[Groucho2004]

This should work:
mod = 2
f = 1.73
b = a.LanczosResize(round((float(width(a))/f) / float(mod)) * mod, round((float(height(a))/f) / float(mod)) * mod)


Thread with a similar subject here (http://forum.doom9.org/showthread.php?t=167431).

[wonkey_monkey]

I always go for:

width(a)*1.0/f

instead of

float(width(a))/f

As I find it a little less brackety.

Wouldn't C, in the case of int/float, return an int? Whereas Avisynth seems to be returning a floored but invalid (for resize) type?

[Gavino]

Wouldn't C, in the case of int/float, return an int? Whereas Avisynth seems to be returning a floored but invalid (for resize) type?
int/float gives a float in both C and Avisynth.
This gives an error since the resizers expect ints for width and height.

[wonkey_monkey]

But a floored float, is that right? Otherwise why not just do round(width(a)/f)?

[Gavino]

But a floored float, is that right? Otherwise why not just do round(width(a)/f)?
No, the float result is fully accurate, and you can just do round(width(a)/f) (as long as f is known to be a float).

Groucho2004's solution:
b = a.LanczosResize(round((float(width(a))/f) / float(mod)) * mod, round((float(height(a))/f) / float(mod)) * mod)

could be written simply as
b = a.LanczosResize(round((width(a)/f) / mod) * mod, round((height(a)/f) / mod) * mod)

[wonkey_monkey]

Ah! My mistake. I was dividing by an int.

[ajp_anton]

Why not introduce "./" or something similar as a divide that always returns a float?

[Terka]

Thanks guys for help!