mpaddict
29th July 2008, 22:24
Hi,
I was wondering if someone could help me decode the following headers:
http://img185.imageshack.us/img185/1416/headersflat201do5.gif
I believe I have most of the IP header decoded, however there are still 4 bytes which I'm unsure as to what they mean. I think bytes 2 and 3 are used to compute the section length (big endian), but I have no clue about bytes 17 and 18. It sort of makes sense that bytes 15 and 16 represent IP length since they add up to "1344 bytes".
http://img530.imageshack.us/img530/5021/headersflat202pa2.gif
I've tried researching UDP and RTP headers online but none of the diagrams I came across seem to match these headers (same with the IP header).
UDP: if I were to guess the second byte (11 = 17 decimal) is some sort of protocol value. I'd also expect a source / destination ip and port in there somewhere.
RTP: So far I'm leaning towards bytes number 3 and 4 being some sort of sequence number and perhaps bytes 5-8 a timestamp?
(I apologize if I posted it in the wrong subforum)
Thank you
I was wondering if someone could help me decode the following headers:
http://img185.imageshack.us/img185/1416/headersflat201do5.gif
I believe I have most of the IP header decoded, however there are still 4 bytes which I'm unsure as to what they mean. I think bytes 2 and 3 are used to compute the section length (big endian), but I have no clue about bytes 17 and 18. It sort of makes sense that bytes 15 and 16 represent IP length since they add up to "1344 bytes".
http://img530.imageshack.us/img530/5021/headersflat202pa2.gif
I've tried researching UDP and RTP headers online but none of the diagrams I came across seem to match these headers (same with the IP header).
UDP: if I were to guess the second byte (11 = 17 decimal) is some sort of protocol value. I'd also expect a source / destination ip and port in there somewhere.
RTP: So far I'm leaning towards bytes number 3 and 4 being some sort of sequence number and perhaps bytes 5-8 a timestamp?
(I apologize if I posted it in the wrong subforum)
Thank you