TheeeGod 3
9th January 2002, 02:01
i recently ripped a movie to my hardrive and have been doing many experiments with it in the CCE part. i read this http://rilanparty.com/vbb/showthread.php?s=&threadid=12718 and began to do it on my own.
at first, i used markrb's personal bitrates to rip this 1hr39min movie. i set the max to 2600, min to 1300, max avg to 2250 and ran CBR with 192 bits of audio. it took about 4 hours and everything seemed fine. the picture was vivid and the sound was clear. the resultant .bins took 1651973 kb and took two cds.
then i decided to crank up the bits. i set the max to 3500, min to 1800, max avg to 3250 and ran 1 pass VBR with a Q factor of 5 and 192 kbs of audio. it took about the same time.when i put it in, i was expecting a a better quality picture. it LOOKED exactly the same. the resultant .bins took 1596231 kb and took two cds.
my next would have been to run multipass vbr = 4 and keep the bitrates that i used in 1 pass vbr. however, the darn thing said like 18 hours and so i said forget it. im guessing the picture would have looked the same. but im not sure how large the files would have been and how many cds would have been required. can anyone guess or figure out?
so my main question is why the two methods if the difference is so minute that the common eye cant decipher it? and which is the most efficient method, meaning that it provides the most quality and the least quantity (as in number of cds used)?
at first, i used markrb's personal bitrates to rip this 1hr39min movie. i set the max to 2600, min to 1300, max avg to 2250 and ran CBR with 192 bits of audio. it took about 4 hours and everything seemed fine. the picture was vivid and the sound was clear. the resultant .bins took 1651973 kb and took two cds.
then i decided to crank up the bits. i set the max to 3500, min to 1800, max avg to 3250 and ran 1 pass VBR with a Q factor of 5 and 192 kbs of audio. it took about the same time.when i put it in, i was expecting a a better quality picture. it LOOKED exactly the same. the resultant .bins took 1596231 kb and took two cds.
my next would have been to run multipass vbr = 4 and keep the bitrates that i used in 1 pass vbr. however, the darn thing said like 18 hours and so i said forget it. im guessing the picture would have looked the same. but im not sure how large the files would have been and how many cds would have been required. can anyone guess or figure out?
so my main question is why the two methods if the difference is so minute that the common eye cant decipher it? and which is the most efficient method, meaning that it provides the most quality and the least quantity (as in number of cds used)?