How to determine if AR of movie is 16/9 or 2.35 ?

[buzzqw]

Using dgindex and avisynth how can i determine if AR in movie is 16/9 or 2.35 ?

I can read from d2v if is 4/3 or 16/9 but if movie is 2.35 in d2v i read

Aspect_Ratio=16:9

NOT

Aspect_Ratio=2.35

there are any possibility (using filters...) ?

thansk !

BHH

[dbzgundam]

Assuming your source is a DVD, you can most likely check the box... If this isn't available, the MPEG2 should have telltale signs.

-If anamorphic, and 16x9, it should take up the whole frame.
-If non-anamorphic, and 16x9, it should only take up a 16x9 part of a 4x3 frame.
-If anamorphic, and 2.35:1... Your eyes sort of have to tell, but it should SORT of look like a 16x9 movie in a 4x3 frame, *when it's not properly displayed*
-If non-anamorphic, and 2.35:1, this follows the same operation as a non-anamorphic 16x9 image... Obviously, it's still just letterboxed into a 4x3 frame.

[Wilbert]

4:3 and 16:9 refer to the DAR, and 2.35 to the PAR. You can't determine whether a movie is 2.35 without looking at the amount of black borders. In contrary to the DAR which is written in the stream itself.

@dbzgundam,
There is no such thing as "non-anamorphic 16x9 image". 16:9 is the same as anamorphic. Fullscreen and letterboxed widescreen are 4:3.

[buzzqw]

4:3 and 16:9 refer to the DAR, and 2.35 to the PAR. You can't determine whether a movie is 2.35 without looking at the amount of black borders. In contrary to the DAR which is written in the stream itself.

Amount of crop...

but ... how to know how is enough... ?


i can
1' case) take the crop value (let's say 72 top, 72 bottom)

720/(576-72-72)=1.666666 -> 16/9

2' case) take crop value (let's say 136 top, 136 bottom)

720/(576-136-136)=2.3684 -> 2.35


could be correct ???

BHH

[dbzgundam]

Originally Posted by Wilbert

4:3 and 16:9 refer to the DAR, and 2.35 to the PAR. You can't determine whether a movie is 2.35 without looking at the amount of black borders. In contrary to the DAR which is written in the stream itself.

@dbzgundam,
There is no such thing as "non-anamorphic 16x9 image". 16:9 is the same as anamorphic. Fullscreen and letterboxed widescreen are 4:3.

That's what I'm referring to, sorry for not using correct terminology!

[Wilbert]

2.35 is not PAR of course, it's just the real aspect ration or whatever you call this.

i can
1' case) take the crop value (let's say 72 top, 72 bottom)

720/(576-72-72)=1.666666 -> 16/9

2' case) take crop value (let's say 136 top, 136 bottom)

720/(576-136-136)=2.3684 -> 2.35

No. You need to know the DAR before you can calculate the real aspect ratio. Suppose your source is 720x576 with DAR 16:9, and black bars 2*72. The real aspect ratio is given by (non ITU compliant):

16/9*576 x 576-2*72 = 1024 x 432 and 1024/432 = 2.3704

If your DAR would be 4:3 you would get

4/3*576 x 576-2*72 = 768 x 432 and 768/432 = 1.7778

I hope it's clear now

[buzzqw]

yep ... it's is clear...

(mumble... mumble...) i will look for a clear solution !

thanks !!!

BHH