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Didée · 19th February 2007, 13:50

I just wanted to make clear that with wrong idx usage like

Code:

green = something
red   = green.process(make_reddish)

vectors1/2/3/4 = green.MVanalyze(...,pel=2,idx=1)

result = red.MVDegrain2(vectors1/2/3/4, idx=1) # idx=1 is incorrect

you end up with a mix of (1*green + 4*red)/5

In your case, you would've created a deblocked clip, and get a mix of 20% deblocked and 80% not-deblocked.

It might not look obviously borked, but it *is* wrong. My radical example shows what's *really* happening then.

19th February 2007, 13:50	#15 \| Link
Didée Registered User Join Date: Apr 2002 Location: Germany Posts: 5,391	I just wanted to make clear that with wrong idx usage like Code: green = something red = green.process(make_reddish) vectors1/2/3/4 = green.MVanalyze(...,pel=2,idx=1) result = red.MVDegrain2(vectors1/2/3/4, idx=1) # idx=1 is incorrect you end up with a mix of (1green + 4red)/5 In your case, you would've created a deblocked clip, and get a mix of 20% deblocked and 80% not-deblocked. It might not look obviously borked, but it is wrong. My radical example shows what's really happening then. __________________ - We´re at the beginning of the end of mankind´s childhood - My little flickr gallery. (Yes indeed, I do have hobbies other than digital video!)