Is it possible to have both DivX 5.05 and DivX 5.1.1 installed

[rmagere]

Hi, just wondering if it is possible to have both DivX 5.05 and DivX 5.1.1 installed as I would like to encode in 5.05 but being able to see movies encoded by 5.1.1 (or use 5.1.1 to view xvids and all divxs).

Sorry if the question is dumb.

[jggimi]

Try this related thread (pointed to in the DivX 5 FAQ, by the way), it may be applicable to your needs:

http://forum.doom9.org/showthread.php?s=&threadid=19300

[rmagere]

Thanks for your help.

[dTb]

That link seems somewhat outdated, I'll explain what I do.

Install the older version of divx, goto the system32 folder and rename divx.dll to say divx505.dll.
Then install the newer version of divx.
Then goto regedit and search for vidc.divx, it's under this string for me in winxp

HKEY_LOCAL_MACHINE\SOFTWARE\Microsoft\Windows NT\CurrentVersion\Drivers32

Make a new string, give it a value name of vidc.divy for example and give it the value data of divx505.dll

And that's basically it, you should now see two versions of divx in encoding apps like vdub, as each video has two fourcc codes the video created with the divy code will still be decoded properly.
Installing divx 5.1.1 second ensures it's decoder will decode all divx video.
To undo all this simply reverse the procedure, uninstalling 5.1.1 first then renaming divx505.dll back to divx.dll and uninstalling 5.0.5.

[no_operation]

See also:

http://forum.doom9.org/showthread.php?threadid=61803

[rmagere]

Again thanks for your replies.

[kots]

is it ok if i do the same but use divx 5.0.2 and not divx 5.0.5?

[rmagere]

I think it should be fine, and I also had a though about doing that as I always encode in 5.05 using "original 2 pass" method rather than the multipass one.

[kots]

what do you mean by saying "i am using original 2 pass method"? what is the "original".

do you simply mean 2 pass method?

[rmagere]

If you look into the divx encoding setting the following are the options available:
1-pass
1-pass quality based
multi-pass 1st pass
multi-pass nth pass
original 1-pass
original 2-pass 1st pass
original 2-pass 2nd pass

So instead of using the multi-pass 1st pass and multi-pass nth pass once (which gives an overall of 2 passes) I set my first pass to original 2-pass 1st pass and my second pass to original 2-pass 2nd pass. Allegedly the original passes should use the same algorithm of 5.02