tpham
28th April 2003, 01:54
Please don't ask me to read the instructions or search the forum as I've done this many times and still I am not able to fully understand how to do it. My problem is determining how many cds to use for my encodes...the following is a problem I had on the weekend and is a problem I have everytime I do an encode. I am encoding 12 chapters of karaoke music with a total time of 128 minutes and choose to use the standard bitrate calculation as defined below.
between 0 - 50 mins. Use 1 CD size 740
between 50 - 76 mins. Use 1 CD size 800
between 76 - 100 mins. Use 2 CD size 740
between 100 - 125 mins. Use 2 CD size 800
between 125 - 163 mins. Use 3 CD size 740
between 163 - 999 mins. Use 3 CD size 800
MaxBitrate=2530 MinBitrate=300 MaxAvg=2230 MinAvg=1600
What I thought was because the total lenght of my music is 128 minutes I can try and fit it on 2 800 mb cds by adjusting the bitrate as
between 100 - 129 mins. Use 2 CD size 800
The final encode produced a .bin that was 810 mb which would fit just 1 800 mb cd. By having only 1 cd the quality would be a lot less that if 2 cds were produced right? What am I doing wrong? Can someone please help me...I can't seem to do this correctly. What I want to be able to do is for example - if I had a 119 minute movie and I want to put it on 3 x 740 mb cds how do I do this??? This is how I've done it in the past (doesn't work too well)
between 0 - 40 mins. Use 1 CD size 740
between 40 - 80 mins. Use 2 CD size 740
between 80 - 120 mins. Use 3 CD size 740
between 120 - 160 mins. Use 4 CD size 740
between 160 - 200 mins. Use 5 CD size 740
between 200 - 999 mins. Use 6 CD size 740
MaxBitrate=2530 MinBitrate=300 MaxAvg=2230 MinAvg=1600
AM I DOING IT ALL WROING???
between 0 - 50 mins. Use 1 CD size 740
between 50 - 76 mins. Use 1 CD size 800
between 76 - 100 mins. Use 2 CD size 740
between 100 - 125 mins. Use 2 CD size 800
between 125 - 163 mins. Use 3 CD size 740
between 163 - 999 mins. Use 3 CD size 800
MaxBitrate=2530 MinBitrate=300 MaxAvg=2230 MinAvg=1600
What I thought was because the total lenght of my music is 128 minutes I can try and fit it on 2 800 mb cds by adjusting the bitrate as
between 100 - 129 mins. Use 2 CD size 800
The final encode produced a .bin that was 810 mb which would fit just 1 800 mb cd. By having only 1 cd the quality would be a lot less that if 2 cds were produced right? What am I doing wrong? Can someone please help me...I can't seem to do this correctly. What I want to be able to do is for example - if I had a 119 minute movie and I want to put it on 3 x 740 mb cds how do I do this??? This is how I've done it in the past (doesn't work too well)
between 0 - 40 mins. Use 1 CD size 740
between 40 - 80 mins. Use 2 CD size 740
between 80 - 120 mins. Use 3 CD size 740
between 120 - 160 mins. Use 4 CD size 740
between 160 - 200 mins. Use 5 CD size 740
between 200 - 999 mins. Use 6 CD size 740
MaxBitrate=2530 MinBitrate=300 MaxAvg=2230 MinAvg=1600
AM I DOING IT ALL WROING???