View Full Version : Total Capacity
bairradino
5th February 2003, 09:37
For a video purpose which is the total capacity, in bytes, that we can put on a DVD +R/ +RW?
benza
5th February 2003, 09:47
4.700.000.000 bytes
oddyseus
5th February 2003, 16:51
Correction!
It is exactly 4.699.979.776bytes
Eyes`Only
6th February 2003, 03:38
Sorry to say, you're both wrong.
DVDr actually holds 4.381 Gigs (4,704,317,440 bytes).
Bytes in a Sector = 2048.
Standard DVDR capacity: 2,297,888 sectors.
FileSystem Overhead= 858 Sectors. (2048*2,297,888)-(2048*858)
Total= 4,704,317,440. 4,704,317,440 bytes=approx. 4.381237 Gigs.
I don't recommend using these figures when you're trying to determine CCE bitrates or whatnot. 4,700,000,000 should suffice and will give you a margin of error.
oddyseus
6th February 2003, 09:49
Thank u Eyes for this inside info.
bairradino
6th February 2003, 10:34
Many Thanks for all of you, particularly you Eyes.
Eyes`Only
6th February 2003, 17:06
No worries. Glad to help. Just wanted to help you understand when that occasion comes that you go to burn a video that's over 4.7gigs and don't get an error. Now you'll know why it worked ;)
wasp
17th March 2004, 14:45
What about DVD+R / DVD+RW / DVD-RW
Because Eyes`Only response was about DVD-R standard only...
and based on my observation DVD+R have got a little bit less space available than DVD-R... about...????
Eyes`Only
17th March 2004, 15:16
Ahh... very keen observation! DVD+R holds a bit less: 4.377 Gigs (4,700,372,992 bytes with 2,295,104 Sectors).
wasp
17th March 2004, 17:07
... but:
4.377 Gigs (4,700,372,992 bytes with 2,295,104 Sectors)
is free space which I may use for data only or free data space + file system???
What about -RW / +RW data capacity (w/o file systems)???
?
Matthew
17th March 2004, 22:47
@wasp, my understanding is that a DVD-R, for example, will not hold a VIDEO_TS directory that is 4,704,317,440 in size. Rather, it will only hold an image that is 4,704,317,440 in size.
Eyes`Only
18th March 2004, 04:14
FileSystem Overhead= 858 Sectors. (2048*2,297,888)-(2048*858)
Free space for data. The header is already subtracted from that amount. What Matthew stated is correct and is the way I test whether or not it will fit anyway :)
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