bitrates in 2 pass vbr

[thingimijig]

i have a film 4 hours long and when i put all the info into the calc it comes up with no lower than 2050kbps (not bothered about the quality).

what do you put in the min,max and average cause everytime i try different things i always end up with a file similar size to what i have.


thingimijig.

[jankster]

Here is how I do it for multi pass mode (I always use min of 2 passes, which is really 3, the first builds a database) All I'll do is 1 video and 1 ac3 track.

This procedure is dead on everytime.

All file sizes are determined by "right-click/properties" in MS Explorer. I'll use made up numbers.

First open the AC3 track with "AC3delayCorrector". Right down the total number of audio frames and divide by 31.25 lets say the result is 9023.44 seconds.

4700 MB ---max DVD-R size
-100 MB ---VOB navigation packs
-20 MB ---extra buffer because I've gone over a little b4
-450.34 ----AC3 track (remember "right-click/properties")
===========================================================
4129.66/9023.44*8000=3661

In CCE use 3661 as the average bit rate. Set min=0, max=9000

the 8000 converts from mega bytes to kilo bits.

[thingimijig]

thanks for the reply jankster.

it sounds like you have it sussed but you lost me on how you actually came up with the final figure.

the part that i just cant get my head round is.

4129.66/9023.44*8000=3661

i can see that the 4129.66 is what you have left to play with for video, but what is the process to get the figure 3661.

would appreciate a small guide if you have the time please.

thingimijig.

[thingimijig]

DOH!

sorry, wasnt looking at it in a mathimatical view.

/ means divide
* means multiply.

thanks again.

thingimijig.