Curious DVD(It is L0<L1)

[jinjin_jp]

A certain DVD becomes a topic in Japan recently.
It is said to be impossible to burn by ImgBurn with using DVDDecrypter's MDS.
So I confirmed and found curious things.

Info of DVDDecrypter
**********************************************
Track Path: Parallel Track Path (PTP)
Linear Density: 0.293 um/bit
Track Density: 0.74 um/track
First Physical Sector of Data Area: 196,608
Last Physical Sector of Data Area: 1,933,775
Last Physical Sector in Layer 0: 0
Layer Information:
Layer 0 Sectors: 1,737,168 (49.97%)
Layer 1 Sectors: 1,739,123 (50.03%)**********************************************
1. It is L0<L1. I think it will be the reason of impossible to burn with MDS.
2. It is PTP. Does PTP allow L0<L1?
3. The values of "Last Physical Sector of Data Area" and "Last Physical Sector in Layer 0" are different from OTP.

Regards.

[bigotti5]

DVD+R DL and DVD-R DL are preformatted as OTP...

Yes, PTP allows L0<L1

[jinjin_jp]

Yes, PTP allows L0<L1
I've never known.
Thanks for the information.

Regards.

[FrozenDog]

Here is some info taken from Scenarist help file.

[nevragain]

this post has some info on why PTP or OTP would be used

http://forum.videohelp.com/topic225001-30.html?sid=1133dff92c8c6077e7ef6a1949f89d24#1008678

:helpful:

there was a way to backup without re-authoring but i cant seem to find the info

[jinjin_jp]

ImgBurn is excellent program.

It burns without problem.
It sets new Layer-Break where the first boundary of VOBU which agree with ECC block after over half of size, when burning with using MDS.

(Sorry, I should have post "DVD burning" sub-Forum.)

Regards.