View Full Version : Video Framerate ??
EpheMeroN
7th July 2006, 08:44
I have a 23.976fps video that I am encoding to dvd and applying pulldown to making it 29.97fps.
I want to add 5-minute chapter points when I author the dvd in MuxMan, but MuxMan only accepts frame numbers. Is there a simple formula that I can use to figure out the new amount of frames caused from the pulldown?
The original has 110453 frames.
Awatef
7th July 2006, 11:27
divide by 23.976 and multiply by 29.97
By the way, don't tell me you encoded your video in interlaced form? if you did, go back to square 1 and re-encode in progressive form with pulldown *FLAGS*. That will improve quality tremendously!
mpucoder
7th July 2006, 14:57
Pulldown requires progressive pictures to work, you cannot pulldown interlaced pictures.
5 seconds is 150 frames in non-drop notation. If you want to correct for the actual playback speed reduce the frame number by one for every 1001 frames like this: (150*chapter_number*1000)/1001
Cells, and therefore the chapters pointing to them, start on a GOP, so the actual chapter point may not be exactly what you requested (it may be up to 0.5 seconds later). This error will not accumulate, though, each cell point is determined individually. The log (default location is C:\muxman.log) will show you the requested and actual times.
The actual number of displayed frames after pulldown depends on the program that did the pulldown. Taking the original number of frames and multiplying by 1.25 should get you within one frame of the actual number. The Muxman log will tell you the total number of fields, divide this by 2 for frames.
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